Contingut

# MIDB

Retorna la cadena de text d'un text DBCS. Els paràmetres indiquen la posició inicial i el nombre de caràcters.

Aquesta funció és disponible des de la versió 4.2 del LibreOffice.

#### Sintaxi

MIGB("Text"; Inici; NombreBytes)

Text és el text que conté els caràcters que s'han d'extreure.

Inici és la posició del primer caràcter del text que s'ha d'extreure.

NombreBytes indica el nombre de caràcters que MIDB retornarà del text, en bytes.

#### Exemple

=MIDB("中国";1;0) returns "" (0 bytes is always an empty string).

=MIDB("中国";1;1) returns " " (1 byte is only half a DBCS character and therefore the result is a space character).

=MIDB("中国";1;2) returns "中" (2 bytes constitute one complete DBCS character).

=MIDB("中国";1;3) returns "中 " (3 bytes constitute one and a half DBCS character; the last byte results in a space character).

=MIDB("中国";1;4) returns "中国" (4 bytes constitute two complete DBCS characters).

=MIDB("中国";2;1) returns " " (byte position 2 is not at the beginning of a character in a DBCS string; 1 space character is returned).

=MIDB("中国";2;2) returns " " (byte position 2 points to the last half of the first character in the DBCS string; the 2 bytes asked for therefore constitutes the last half of the first character and the first half of the second character in the string; 2 space characters are therefore returned).

=MIDB("中国";2;3) returns " 国" (byte position 2 is not at the beginning of a character in a DBCS string; a space character is returned for byte position 2).

=MIDB("中国";3;1) returns " " (byte position 3 is at the beginning of a character in a DBCS string, but 1 byte is only half a DBCS character and a space character is therefore returned instead).

=MIDB("中国";3;2) returns "国" (byte position 3 is at the beginning of a character in a DBCS string, and 2 bytes constitute one DBCS character).

=MIDB("office";2;3) returns "ffi" (byte position 2 is at the beginning of a character in a non-DBCS string, and 3 bytes of a non-DBCS string constitute 3 characters).